Day 10: Binary Numbers

Objective
Today, we're working with binary numbers. Check out the Tutorial tab for learning materials and an instructional video!

Task
Given a base- integer, , convert it to binary (base-). Then find and print the base- integer denoting the maximum number of consecutive 's in 's binary representation. When working with different bases, it is common to show the base as a subscript.

Example

The binary representation of  is . In base , there are  and  consecutive ones in two groups. Print the maximum, .

Input Format

A single integer, .

Constraints

Output Format

Print a single base- integer that denotes the maximum number of consecutive 's in the binary representation of .

Sample Input 1

5

Sample Output 1

1

Sample Input 2

13

Sample Output 2

2

Explanation

Sample Case 1:
The binary representation of  is , so the maximum number of consecutive 's is .

Sample Case 2:
The binary representation of  is , so the maximum number of consecutive 's is .

//importing all header files
#include <assert.h>
#include <ctype.h>
#include <limits.h>
#include <math.h>
#include <stdbool.h>
#include <stddef.h>
#include <stdint.h>
#include <stdio.h>
#include <stdlib.h>
#include <string.h>

char* readline();
char* ltrim(char*);
char* rtrim(char*);

int parse_int(char*);

int main()
{
    int n = parse_int(ltrim(rtrim(readline())));
    int currentConsecutive=0,maxConsecutive=0;
    while(n&gt;0){
        if(n%2==1){
            currentConsecutive++;
            if (currentConsecutive &gt; maxConsecutive)  
                     maxConsecutive = currentConsecutive;  
           } else {  
                currentConsecutive = 0;  
           }  
           n /= 2;  
      }  
    printf("%d",maxConsecutive);

    return 0;
}

char* readline() {
    size_t alloc_length = 1024;
    size_t data_length = 0;

    char* data = malloc(alloc_length);

    while (true) {
        char* cursor = data + data_length;
        char* line = fgets(cursor, alloc_length - data_length, stdin);

        if (!line) {
            break;
        }

        data_length += strlen(cursor);

        if (data_length &lt; alloc_length - 1 || data[data_length - 1] == '\n') {
            break;
        }

        alloc_length &lt;&lt;= 1;

        data = realloc(data, alloc_length);

        if (!data) {
            data = '\0';

            break;
        }
    }

    if (data[data_length - 1] == '\n') {
        data[data_length - 1] = '\0';

        data = realloc(data, data_length);

        if (!data) {
            data = '\0';
        }
    } else {
        data = realloc(data, data_length + 1);

        if (!data) {
            data = '\0';
        } else {
            data[data_length] = '\0';
        }
    }

    return data;
}

// removing left side spaces in input
char* ltrim(char* str) {
    if (!str) {
        return '\0';
    }

    if (!*str) {
        return str;
    }

    while (*str != '\0' &amp;&amp; isspace(*str)) {
        str++;
    }

    return str;
}

// removing  right side spaces in input
char* rtrim(char* str) {
    if (!str) {
        return '\0';
    }

    if (!*str) {
        return str;
    }

    char* end = str + strlen(str) - 1;

    while (end &gt;= str &amp;&amp; isspace(*end)) {
        end--;
    }

    *(end + 1) = '\0';

    return str;
}

int parse_int(char* str) {
    char* endptr;
    int value = strtol(str, &amp;endptr, 10);

    if (endptr == str || *endptr != '\0') {
        exit(EXIT_FAILURE);
    }
    
   return value;
}